PYL 105: Lab 4

Forces and Vectors

According to Newton's Second Law

F = m a,

if there is a net force acting on an object, then the object will accelerate. In this experiment we will consider a situation of static equilibrium, i.e. a case in which nothing is moving. If an object is not moving, then it is certainly not accelerating. And then using Newton's Second Law we can further conclude that there is no net force on the object. No net force does not mean there are no forces on the object, nor does it mean no motion, but rather that the effects of all of the individual forces cancel, and there is no acceleration (no change in whatever the velocity might be).

Forces have a both a magnitude and a direction. The magnitude tells one the size of the push or pull supplied by the force, while the direction tells which way the object is being pushed or pulled. Forces are thus represented mathematically by vectors. A quantity must have certain properties in order for it to be considered a vector. For instance, there are rules expressing vectors in terms of components and rules for adding vectors.

Expressing a vector in terms of its components is also known as "resolving" it. Let us consider resolving a force F into components. Find the angle between the x axis and F as shown below. There are two conventions for measuring angles:

  1. To measure the angle starting from the positive x axis, proceeding in a counter-clockwise direction and ending on the vector of interest. This approach results in angles between 0 and 360 degrees.
  2. To measure the angle between the x axis (positive or negative, whichever is closer) and the vector of interest. This approach yields angles between 0 and 90 degrees, and one must further keep track of which quadrant the vector lies in.

We'll adopt the second method in the following discussion. Another thing to keep in mind when dealing with angles is to keep track of whether one is working with degrees or radians.


We can think of F and its x and y components (Fx and Fy) as the sides of a right triangle, with F as the hypoteneuse and the components as the legs. Using the trigonometric relation that

cos q = adjacent / hypoteneuse

we can determine that with the angle as drawn above, Fx, the x component of F is, up to a sign, given by

Fx = |F| cos q

where |F| is the magnitude of F. Similarly, up to a sign the y component of F3 is given by

Fy = |F| sin q

the magnitude of F times sin theta. The signs can be determined by what quadrant one is in

Quadrant Sign of x
component
Sign of y
component
I
+
+
II
-
+
III
-
-
IV
+
-

Part I. Calibrating the Force Sensor.

Do you observe any errors in your force sensor readings? If so, are they systematic or random? Explain.

Part II. Resolving the force vector into components.

Are the sums of the components acceptably close to zero? (Take into account any Force Sensor errors you observed in part I.)

Part III. Adding vectors.

Did Force 3 change substantially when you replaced Forces 1 and 4 with Force G? Are any differences acceptable? Explain.

Part IV Pulley Effect

Arrange your apparatus based on the figure below.  When W1 (pan and added mass) has a mass of 100g what is the sensor's reading?  Repeat with 150g, 200g and 250g.  What is the sensor holding up?  With the 250g attached slowly pull the force sensor 4cm.  By how much does W1 move?