Lab 4: Forces and Vectors

According to Newton's Second Law

F = m a,

where F is the net external force acting on an object. In this experiment we will consider the situation of static equilibrium, i.e. a case in which nothing is moving. If an object is not moving, then it is not accelerating and Newton's Second Law implies that there is no net force on the object.

Note that "no net force" does not mean there are no forces on the object, nor does it mean no motion. Instead, it implies that that the effects of all of the forces acting on the object cancel, and there is no acceleration (i.e. no change in the velocity of the object).

Forces have a both a magnitude and a direction. The magnitude is the size of the push or pull supplied by the force, while the direction describes in which the force is applied to an object. Forces must then be represented mathematically by vectors. The net force is then necessarily a vector sum, which may be calculated algebraically by using vector components.

Expressing a vector in terms of its components is also known as "resolving" the vector. Consider F in the following diagram. To resolve F into components, find the angle between the x-axis and F as shown. There are two conventions for measuring angles:

  1. Measure the angle starting from the positive x-axis, proceeding in a counter-clockwise direction and ending on the vector of interest. This approach results in angles between 0 and 360 degrees.
  2. Measure the angle between the x-axis (positive or negative, whichever is closer) and the vector of interest. This approach yields angles between 0 and 90 degrees, and one must make note of which quadrant the vector lies in.

We'll adopt the second method in the following discussion. Another thing to keep in mind when dealing with angles is to keep track of whether degrees or radians are the units.

We can think of F and its x and y components (Fx and Fy) as the sides of a right triangle, with F as the hypotenuse and the components as the legs. Using the trigonometric relation

cos θ = adjacent / hypotenuse

we can determine that with the angle as drawn above, Fx, the x-component of F is, up to a sign, given by

Fx = |F| cos θ

where |F| is the magnitude of F. Similarly, up to a sign the y component of F3 is given by

Fy = |F| sin θ

The signs of the components are determined by the quadrant location of the vector.

Table 1: Quadrants and Vector Components
Quadrant Sign of x-component Sign of y-component
I + +
II +
III
IV +

Part I. Calibrating the Force Sensor.

Table 2: Experimental vs. Theoretical Force
Mass (kg) Force(N) Measured Force(N) Theory (mg)
0.150    
0.250    
0.350    

Part II. Resolving the force vector into components.

Analysis
Table 3: Vector Sum of 3 Forces in Equilibrium - Trial 1
  Magnitude Angle Quadrant Fx Fy
Force 1          
Force 2          
Force 3          
      Sum    
Table 4: Vector Sum of 3 Forces in Equilibrium - Trial 2
  Magnitude Angle Quadrant Fx Fy
Force 1          
Force 2          
Force 3          
        Sum  

Be sure to comment on the nature of the error in this lab in your lab report!